JEE Main & Advanced Sample Paper JEE Main Sample Paper-16

  • question_answer
    Copper contains \[8.4\times {{10}^{28}}\] free electrons/\[{{m}^{3}}\]. A copper wire of cross-sectional area \[7.4\times {{10}^{-7}}\]\[{{m}^{2}}\] carries a current of 1 A. The electron drift speed is approximately:

    A) \[{{10}^{-8}}\text{m/s}\]                             

    B) \[{{10}^{3}}\text{m/s}\]

    C) \[\text{1}\,\text{m/s}\]                                               

    D) \[{{10}^{-4}}\text{m/s}\]

    Correct Answer: D

    Solution :

    \[J=nev\] \[v=\frac{I}{ne}=\frac{1}{7.4\times {{10}^{-7}}}\times 8.4\times {{10}^{28}}\] \[=\frac{{{10}^{-2}}}{8.4\times 1.6\times 7.4}\]


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