A) 2 M
B) 1.5 M
C) 1 M
D) 0.5 M
Correct Answer: B
Solution :
No. of moles of \[CuS{{O}_{4}}=2\times 2=4\] Equivalent wt of \[CuS{{O}_{4}}=\frac{{{M}_{CuS{{O}_{4}}}}}{2}\] 1C charge will deposit\[\frac{E}{96500}\]gm of \[C{{u}^{2+}}\] {E=Equivalent wt} \[\therefore \]\[2\times 96500C\]will deposit \[=2\times 96500\times \frac{E}{96500}=2E={{M}_{CuS{{O}_{4}}}}\] \[\therefore \]No of moles remaining \[=4-1=3\]moles \[\therefore \]Molarity\[=\frac{3}{2}=1.5\,\text{M}\]You need to login to perform this action.
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