A) \[\mu >\frac{1}{2\sqrt{3}}\]
B) \[\mu <\frac{1}{2\sqrt{3}}\]
C) \[\mu >\frac{\sqrt{3}}{2}\]
D) \[\mu <\frac{\sqrt{3}}{2}\]
Correct Answer: A
Solution :
\[F\times \sqrt{3}a\,mg\frac{a}{2}=0\] \[F\times \frac{mg}{2\sqrt{3}}\le \mu \,mg\] \[\Rightarrow \mu \ge \frac{1}{2\sqrt{3}}\]You need to login to perform this action.
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