A) \[\text{q}\,\text{=}\,\text{C}\,\text{(V}\,\text{+}\,\text{2}\,\text{V}{{\text{e}}^{\text{-t/RC}}}\text{)}\]
B) \[\text{q}\,\text{=}\,\text{C}\,\text{(V}\,-\,\text{2}\,\text{V}{{\text{e}}^{\text{-t/RC}}}\text{)}\]
C) \[\text{q}\,\text{=}\,\text{C}\,\text{(V}\,+\,\text{2}\,\text{V}{{\text{e}}^{\text{-t/2RC}}}\text{)}\]
D) \[\text{q}\,\text{=}\,\text{C}\,\text{(V}\,+\,\text{2}\,\text{V}{{\text{e}}^{\text{-2t/RC}}}\text{)}\]
Correct Answer: C
Solution :
\[Q={{Q}_{0}}{{e}^{-t/RC}}+CV(1-{{e}^{-t/RC}})\] \[=\left( CV+2CV\,{{e}^{-t/2RC}} \right)\] \[i=\frac{d\theta }{dt}=2CV\times \frac{{{e}^{-t/2RC}}}{2RC}\]You need to login to perform this action.
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