A) 0.68 MeV
B) 0.84 MeV
C) 0.75 MeV
D) 1.22 MeV
Correct Answer: B
Solution :
\[_{0}^{1}n\to _{1}^{1}p+_{-1}^{0}e\] \[Q=({{m}_{n}}-{{m}_{p}}-{{m}_{e}}){{c}^{2}}\] \[=0.0009\times 931.5\]You need to login to perform this action.
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