A) 20%
B) 30%
C) 40%
D) 50%
Correct Answer: C
Solution :
Equivalent of NaOH left = Equivalent of acid \[1\times {{V}_{ml}}=60\times 1\] \[\therefore \]\[{{V}_{ml}}=60ml\] \[{{({{V}_{NaOH}})}_{used}}=100-60=40\,ml\] \[N{{H}_{4}}^{+}+O{{H}^{-}}\xrightarrow[{}]{{}}N{{H}_{3}}+{{H}_{2}}O\] No. of equivalents of NaOH= No. of equivalent of \[NH_{4}^{+}\]salt\[40\times 1\times {{10}^{-3}}=\]No. of eq. of \[NH_{4}^{+}\] Wt. of ammonia\[=40\times {{10}^{-3}}\times 17\]% of ammonia in salt\[=\frac{40\times {{10}^{-3}}\times 17}{1.7}\times 100=40%\]You need to login to perform this action.
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