A) \[\left[ \frac{-1}{2},\frac{1}{2} \right]\]
B) \[\left[ 0,\frac{1}{2} \right]\]
C) \[(-1,1)\]
D) \[\left[ \frac{-1}{2},0 \right]\]
Correct Answer: A
Solution :
\[-1\le \frac{4{{\tan }^{-1}}(2x)}{\pi }\le 1\]or\[\frac{-\pi }{4}\le {{\tan }^{-1}}(2x)\le \frac{\pi }{4}\] \[\Rightarrow \]\[=1\le 2x\le 1\]or\[x\in \left[ \frac{-1}{2},\frac{1}{2} \right]\]You need to login to perform this action.
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