JEE Main & Advanced Sample Paper JEE Main Sample Paper-16

  • question_answer
    When force F acts on side of hexagonal body for what range of coefficient of friction will body topple?

    A) \[\mu >\frac{1}{2\sqrt{3}}\]                       

    B) \[\mu <\frac{1}{2\sqrt{3}}\]

    C) \[\mu >\frac{\sqrt{3}}{2}\]                         

    D) \[\mu <\frac{\sqrt{3}}{2}\]

    Correct Answer: A

    Solution :

    \[F\times \sqrt{3}a\,mg\frac{a}{2}=0\] \[F\times \frac{mg}{2\sqrt{3}}\le \mu \,mg\] \[\Rightarrow \mu \ge \frac{1}{2\sqrt{3}}\]


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