A) \[{{10}^{-4}}M\]
B) \[{{10}^{-6}}M\]
C) \[2\times {{10}^{-6}}M\]
D) \[2\times {{10}^{-5}}M\]
Correct Answer: B
Solution :
\[\underset{0}{\mathop{Ca{{(OH)}_{2}}}}\,\] | \[\xrightarrow[{}]{{}}\]\[\underset{0.5}{\mathop{C{{a}^{2+}}}}\,\]+ | \[\underset{1+x}{\mathop{2O{{H}^{-}}}}\,\] |
\[\underset{0.1-x}{\mathop{N{{H}_{4}}OH}}\,\] | \[\xrightarrow[{}]{{}}\]\[\underset{x}{\mathop{N{{H}_{4}}^{+}}}\,\]+ | \[\underset{1+x}{\mathop{O{{H}^{-}}}}\,\] |
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