A) 1
B) (2) 2
C) 3
D) 4
Correct Answer: D
Solution :
For\[{{x}^{2}}=9a(9-y);\]\[\frac{dy}{dx}=\frac{-2x}{9a}={{m}_{1}}\] For\[{{x}^{2}}=a(y+1);\]\[\frac{dy}{dx}=\frac{2x}{a}={{m}_{2}}\] \[{{m}_{1}}{{m}_{2}}=-1\]gives\[4{{x}^{2}}=9{{a}^{2}}\] ?(1) also by eliminating ?y? between the equation of curves \[{{x}^{2}}=9a\] ?(2) from (1) and (2), we get a = 4You need to login to perform this action.
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