A) parabolic path
B) circular path
C) straight line path
D) elliptical path
Correct Answer: C
Solution :
\[{{\bar{v}}_{CM}}=\frac{{{m}_{1}}{{{\vec{v}}}_{1}}+{{m}_{2}}{{{\vec{v}}}_{2}}}{{{m}_{1}}{{m}_{2}}}=\frac{6\hat{i}+6\hat{j}}{5}\] and \[{{\vec{a}}_{CM}}=\frac{{{m}_{1}}{{{\vec{a}}}_{1}}+{{m}_{2}}{{{\vec{a}}}_{2}}}{{{m}_{1}}{{m}_{2}}}=\frac{6\hat{i}+6\hat{j}}{5}\] Since\[{{\vec{v}}_{CM}}||{{\vec{a}}_{CM}},\]centre of mass follows a straight line path.You need to login to perform this action.
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