A) g/3
B) g
C) g/4
D) 2g
Correct Answer: B
Solution :
Since the pulley is light, the mass of pulley can be considered as zero is shown here. The Free Body Diagram of pulley is shown here \[2T-T=0\times a\] \[\Rightarrow \] \[T=0\] Since tension in string comes out to be zero, both the blocks fall under gravity.You need to login to perform this action.
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