A) 7 litres
B) 14 litres
C) 2 litres
D) None of these
Correct Answer: B
Solution :
\[{{H}_{2}}+C{{l}_{2}}\to 2\,HCl\] Volume before reaction \[8L\,\,\,6L\,\,\,0L\] Volume after reaction \[2L\,\,\,0L\,\,\,12L\] Volume after reaction = Volume of \[{{H}_{2}}\]left + Volume of \[HCl\]formed \[=2+12=14\,L.\]You need to login to perform this action.
You will be redirected in
3 sec