A) \[21.2\times {{10}^{-18}}\,\text{J/atom}\]
B) \[44.10\times {{10}^{-18}}\,\text{J/atom}\]
C) \[63.2\times {{10}^{-18}}\,\text{J/atom}\]
D) \[84.2\times {{10}^{-18}}\,\text{J/atom}\]
Correct Answer: B
Solution :
\[{{\text{E}}_{\text{1}}}\]for \[\text{L}{{\text{i}}^{+2}}={{E}_{1}}\]for\[H\times Z_{Li}^{2}={{E}_{1}}\]for \[H\times 9\] Also, \[{{E}_{1}}\]for \[H{{e}^{+}}={{E}_{1}}\]for \[H\times Z_{He}^{2}={{E}_{1}}\]for \[H\times 4\] or \[{{E}_{1}}\]for \[L{{i}^{+2}}=\frac{9}{4}{{E}_{1}}\]for \[H{{e}^{+}}\] \[=19.6\times {{10}^{-18}}\times \frac{9}{4}\] \[=44.10\times {{10}^{-18}}\,\text{J/atom}\]
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