A) \[(0,2]\]
B) \[(1,8)\]
C) \[(-8,1]\]
D) None of these
Correct Answer: C
Solution :
\[\text{Sum}=\frac{\frac{x}{r}}{1-r}=4\](where \[r\]is common ratio) \[x=4r(1-r)\] \[=4(r-{{r}^{2}})\] For \[r\in (-1,1),\] \[r-{{r}^{2}}\in \left( -2,\frac{1}{4} \right)\] \[\Rightarrow \] \[x\in (-8,1]\]You need to login to perform this action.
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