JEE Main & Advanced Sample Paper JEE Main Sample Paper-17

  • question_answer
    The coefficient of\[{{x}^{50}}\]in\[(x+{{\,}^{101}}{{C}_{0}})(x{{+}^{101}}{{C}_{1}})...(x{{+}^{101}}{{C}_{50}})\]is

    A) \[{{4}^{50}}\]                                    

    B) \[{{2}^{50}}\]

    C) \[{{2}^{101}}-1\]              

    D) \[{{2}^{101}}\]

    Correct Answer: A

    Solution :

     \[(x+{{\,}^{101}}{{C}_{0}})(x+{{\,}^{101}}{{C}_{0}})...(x+{{\,}^{101}}{{C}_{50}})\]contains 51 linear factors. Thus, x50 is obtained by multiplying \[x's\] from any 50 factors and the constant term from the remaining one factor. Hence, the coefficient of\[{{x}^{50}}=S={{\,}^{101}}{{C}_{0}}{{+}^{101}}{{C}_{1}}+...\]\[+\,{{\,}^{101}}{{C}_{50}}\] Noting that \[{{\,}^{101}}{{C}_{51}}={{\,}^{101}}{{C}_{50}},{{\,}^{101}}{{C}_{101}}={{\,}^{101}}{{C}_{0}}\]etc., We see that \[2S={{\,}^{101}}{{C}_{0}}{{+}^{101}}{{C}_{1}}+...{{+}^{101}}{{C}_{50}}{{+}^{101}}{{C}_{51}}+...{{+}^{101}}{{C}_{101}}\]                \[={{2}^{101}}\] \[\Rightarrow \]               \[S={{2}^{100}}={{4}^{50}}\]


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