A) equilateral triangle
B) right angled triangle
C) obtuse angled triangle
D) isosceles triangle and\[\angle ABC=\frac{\pi }{6}\]
Correct Answer: A
Solution :
Radius of the circles are same. \[\Rightarrow \] \[AB=AC\] Also if \[\theta \]is the angle between the tangents then \[\cos \theta =\frac{12-4-4}{2(2)(2)}=\frac{1}{2}\] \[\Rightarrow \] \[\theta =\frac{\pi }{3}\] Hence, \[\Delta ABC\]is an equilateral triangle.You need to login to perform this action.
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