A) 2
B) 4
C) 6
D) 8
Correct Answer: C
Solution :
\[D=\left| \begin{matrix} k & 4 & 1 \\ 4 & k & 2 \\ 2 & 2 & 1 \\ \end{matrix} \right|=0\] \[\Rightarrow \]\[k(k-4)-4(0)+1(8-2k)=0\] \[\Rightarrow \]\[{{k}^{2}}-6k+8=0\]You need to login to perform this action.
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