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JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    A body cools from\[60{}^\circ C\]to\[50{}^\circ C\]in 10 minutes. If the room temperature is \[25{}^\circ C\] and assuming Newton's laws of cooling to hold good, the temperature of the body at the end of the next 10 minutes will be

    A)  \[38.5{}^\circ C\]                            

    B)  \[40{}^\circ C\]

    C)  \[42.85{}^\circ C\]                          

    D)  \[45{}^\circ C\]

    Correct Answer: C

    Solution :

     \[MS(60-50)=K(55-25)\times 10\] \[MS\,(50-T)=K\times 2\pi \left( \frac{50+T}{2}-25 \right)10\] \[\Rightarrow \]               \[T=42.850{}^\circ C\]


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