A) 2.025 mm
B) 1.025 mm
C) 4.01 mm
D) 5 mm
Correct Answer: A
Solution :
\[\theta =\frac{\beta }{D}=\frac{\lambda }{d}=\frac{\pi }{60\times 180}\] \[\Rightarrow \] \[d=\frac{\lambda \times 60\times 180}{\pi }\] \[=0.2025\,cm\] \[=2.025\,mm\]
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