JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    The capacitor C is initially without charge. X is now joined to Y. for a long time, during which\[{{H}_{1}}\] heat is produced in the resistance R. X is now joined to Z for a long time, during which \[{{H}_{2}}\]heat is produced in R. Then

    A)  \[{{H}_{1}}={{H}_{2}}\]                

    B)  \[{{H}_{1}}=\frac{1}{2}{{H}_{2}}\]

    C)  \[{{H}_{1}}=2{{H}_{2}}\]                              

    D)  \[{{H}_{1}}={{H}_{2}}\text{/}4\]

    Correct Answer: A

    Solution :

     Work done by battery\[=C{{V}^{2}}\] Energy stored in capacitor\[=\frac{1}{2}C{{V}^{2}}\] \[{{H}_{1}}=C{{V}^{2}}-1\text{/}2\,C{{V}^{2}}=1\text{/}2\,C{{V}^{2}}\] So, \[{{H}_{1}}={{H}_{2}}\]


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