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JEE Main & Advanced Sample Paper JEE Main Sample Paper-18

  • question_answer
    Three moles of a gas are present in a vessel at a temperature of\[27{}^\circ C\]. Calculate the value of gas constant (R) in terms of kinetic energy of the molecules of gas.

    A)  \[7.4\times {{10}^{-4}}\]KE per degree kelvin.

    B)  \[4.5\times {{10}^{-4}}\]KE per degree kelvin.

    C)  \[7.4\times {{10}^{-5}}\]KE per degree kelvin.

    D)  None of these

    Correct Answer: A

    Solution :

     KE for 1 mole = 3/2 RT KE for 3 moles = 9/2 RT or  \[R=\frac{2}{9T}KE=\frac{2}{9\,(300)}KE\] \[=7.4\times {{10}^{-4}}KE\]per degree kelvin.


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