A) 0.0856
B) 0.0956
C) 0.1056
D) 0.1156
Correct Answer: C
Solution :
Weight of\[C{{H}_{3}}COOH\]dissolved = 5 g Eq. of\[C{{H}_{3}}COOH\]dissolved\[=\frac{5}{60}\] Volume of ethanol = 1 litre = 1000 ml. \[\therefore \] Weight of ethanol = 1000\[\times \]0.789 = 789 g \[\therefore \] Molality of solution\[=\frac{\text{Moles}\,\text{of}\,\text{solute}}{\text{Weight}\,\text{of}\,\text{solvent}\,\text{in}}\] \[=\frac{\frac{5}{60\times 789}}{1000}=0.1056\]You need to login to perform this action.
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