A) 4
B) 7
C) 10
D) 14
Correct Answer: A
Solution :
\[{{K}_{a}}\times {{K}_{b}}={{K}_{w}}\] \[\Rightarrow \] \[{{K}_{a}}=\frac{{{K}_{w}}}{{{K}_{b}}}=\frac{1\times {{10}^{-14}}}{1\times {{10}^{-10}}}={{10}^{-4}}\] Now, \[pH=p\,{{K}_{a}}+\log \,\frac{[{{X}^{-}}]}{[HX]}\] \[\Rightarrow \] \[pH=p{{K}_{a}}+\log 1=-\,\log \,{{10}^{-4}}+0\] \[=\,4\,\log 10\,=4.\]You need to login to perform this action.
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