A) \[1.6\times {{10}^{-4}}\]
B) \[0.8\times {{10}^{-4}}\]
C) \[6.4\times {{10}^{-4}}\]
D) \[3.2\times {{10}^{-4}}\]
Correct Answer: C
Solution :
The rate of reaction and therefore, velocity constant becomes double for every \[10{}^\circ \] rise in temperature. For \[20{}^\circ \] rise in temperature \['k'\] becomes four times i.e., \[4\times 1.6\times {{10}^{-4}}=6.4\times {{10}^{-4}}\].
You need to login to perform this action.
You will be redirected in
3 sec
