A) \[3ab\]
B) \[3a{{b}^{2}}\]
C) \[3{{a}^{2}}b\]
D) \[3\]
Correct Answer: B
Solution :
\[\sin 10{}^\circ =\frac{a}{2b}\] \[\Rightarrow \] \[\sin 30{}^\circ =3\,\sin 10{}^\circ -4\,{{\sin }^{3}}10\] \[\Rightarrow \] \[\frac{1}{2}=\frac{3a}{2b}-\frac{4{{a}^{3}}}{8{{b}^{3}}}\] \[\Rightarrow \] \[{{a}^{3}}+{{b}^{3}}=3\,a{{b}^{2}}\]You need to login to perform this action.
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