A) \[{{\Delta }_{1}}=3\,{{({{\Delta }_{2}})}^{2}}\]
B) \[\frac{d}{dx}({{\Delta }_{1}})=3{{\Delta }_{2}}\]
C) \[\frac{d}{dx}({{\Delta }_{1}})=3{{({{\Delta }_{2}})}^{2}}\]
D) \[{{\Delta }_{1}}=3{{\Delta }_{2}}^{3/2}\]
Correct Answer: B
Solution :
\[{{\Delta }_{1}}=\,x({{x}^{2}}-ab)-b(ax-ab)+b({{a}^{2}}-ax)\] \[={{x}^{3}}-3abx+a{{b}^{2}}+{{a}^{2}}b\] \[\frac{d}{dx}({{\Delta }_{1}})=3{{x}^{2}}-3ab=3\,({{x}^{2}}-ab)=3{{\Delta }_{2}}\]You need to login to perform this action.
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