A) 4
B) 1
C) 2
D) 3/2
Correct Answer: C
Solution :
Given \[|z|\,=\,\frac{1}{3}\] Let \[w=-1+6\,z\] \[\Rightarrow \] \[z=\frac{w+1}{6}\] \[\Rightarrow \] \[|z|\,=\frac{|w+1|}{6}\] \[\Rightarrow \] \[\frac{1}{3}=\frac{|w+1|}{6}\] \[\Rightarrow \] \[|w+1|\,=2\] \[\Rightarrow \] \[w\] lies on a circle with centre \[-1\] and radius 2.You need to login to perform this action.
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