JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer In an amino acid, the carboxyl group ionises at \[pK\,\,{{a}_{1}}=2.34\] and ammonium ion at \[pK\,\,{{a}_{2}}=9.60\]. The isoelectric point the amino acid is at pH                           

    A)  \[5.97\]                        

    B)  \[2.34\]              

    C)  \[9.60\]                        

    D)  \[6.97\]

    Correct Answer: A

    Solution :

     Isoelectric point (pH) \[=\frac{p{{K}_{{{a}_{1}}}}+p{{K}_{{{a}_{2}}}}}{2}=\frac{2.34+9.60}{2}=5.97\]


You need to login to perform this action.
You will be redirected in 3 sec spinner