• question_answer 14) If the following half cells have the $E{}^\circ$ values as $F{{e}^{+3}}+{{e}^{-}}\xrightarrow{{}}F{{e}^{+2}};$ ${{E}^{o}}=+0.77V$ and $F{{e}^{+2}}+2{{e}^{-}}\xrightarrow{{}}Fe;$${{E}^{o}}=-0.44V.$The ${{E}^{o}}$ of the half cell $F{{e}^{+3}}+3{{e}^{-}}\xrightarrow{{}}Fe$ will be A)  $0.33\,V$                    B)  $1.21\,V$C)  $0.04\,V$                    D)  $0.605\,V$

${{E}^{0}}=\frac{0.77+2(-0.44)}{3}=\frac{0.77-0.88}{3}=-\frac{0.11}{3}$ $\approx -0.04$