JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer If the following half cells have the \[E{}^\circ \] values as \[F{{e}^{+3}}+{{e}^{-}}\xrightarrow{{}}F{{e}^{+2}};\] \[{{E}^{o}}=+0.77V\] and \[F{{e}^{+2}}+2{{e}^{-}}\xrightarrow{{}}Fe;\]\[{{E}^{o}}=-0.44V.\]The \[{{E}^{o}}\] of the half cell \[F{{e}^{+3}}+3{{e}^{-}}\xrightarrow{{}}Fe\] will be

    A)  \[0.33\,V\]                    

    B)  \[1.21\,V\]

    C)  \[0.04\,V\]                    

    D)  \[0.605\,V\]

    Correct Answer: C

    Solution :

     \[{{E}^{0}}=\frac{0.77+2(-0.44)}{3}=\frac{0.77-0.88}{3}=-\frac{0.11}{3}\] \[\approx -0.04\]

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