A) \[CaC{{l}_{2}}\]
B) \[BaC{{l}_{2}}\]
C) \[CuC{{l}_{2}}\]
D) None of these
Correct Answer: B
Solution :
The reagent is \[BaC{{l}_{2}}\] which imparts green colour to flame. \[BaC{{l}_{2}}\] forms chromyl chloride (which is red in colour), when treated with \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] and cone. \[{{H}_{2}}S{{O}_{4}}.\] \[2BaC{{l}_{2}}+{{K}_{2}}C{{r}_{2}}{{O}_{7}}+3{{H}_{2}}S{{O}_{4}}\] \[\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+2BaS{{O}_{4}}+\underset{\begin{smallmatrix} Chromyl\,chloride \\ (red\,\,gas) \end{smallmatrix}}{\mathop{2Cr{{O}_{2}}C{{l}_{2}}}}\,+3{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec
