A) \[C{{H}_{3}}CHO\]
B) \[C{{H}_{3}}COC{{H}_{3}}\]
C) \[HCHO\]
D) 2-propanol
Correct Answer: C
Solution :
Formaldehyde cannot produce iodoform, as only those compound which contains either \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-\] group or \[C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,H-\]group on reaction with potassium iodide and sod. hypochlorite yield iodoform.
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