JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer The hybridization of atomic orbitals of nitrogen in \[NO_{2}^{+},\,NO_{2}^{-}\] and \[NH_{4}^{+}\]are

    A)  \[s{{p}^{2}},s{{p}^{3}}\] and \[s{{p}^{2}}\] respectively

    B)  \[sp,s{{p}^{2}}\] and \[s{{p}^{3}}\] respectively

    C)  \[s{{p}^{2}},sp\] and \[s{{p}^{3}}\] respectively

    D)  \[s{{p}^{2}},s{{p}^{3}}\] and \[sp\] respectively

    Correct Answer: B

    Solution :

     \[NO_{2}^{+}=\frac{1}{2}[5+0+0-1]=2sp;\] \[NO_{2}^{-}=\frac{1}{2}[5+0+1-0]=3s{{p}^{2}};\] \[NO_{4}^{+}=\frac{1}{2}[5+4+0-1]=4s{{p}^{3}};\]

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