A) \[s{{p}^{2}},s{{p}^{3}}\] and \[s{{p}^{2}}\] respectively
B) \[sp,s{{p}^{2}}\] and \[s{{p}^{3}}\] respectively
C) \[s{{p}^{2}},sp\] and \[s{{p}^{3}}\] respectively
D) \[s{{p}^{2}},s{{p}^{3}}\] and \[sp\] respectively
Correct Answer: B
Solution :
\[NO_{2}^{+}=\frac{1}{2}[5+0+0-1]=2sp;\] \[NO_{2}^{-}=\frac{1}{2}[5+0+1-0]=3s{{p}^{2}};\] \[NO_{4}^{+}=\frac{1}{2}[5+4+0-1]=4s{{p}^{3}};\]You need to login to perform this action.
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