JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer The period of the satellite of the earth orbiting very near to the surface of the earth is \[{{T}_{0}}\]. What is the period of the geostationary satellite in terms of \[{{T}_{0}}\]

    A)  \[\frac{{{T}_{0}}}{\sqrt{7}}\]                              

    B)  \[\sqrt{7}{{T}_{0}}\]

    C)  \[7\,\,{{T}_{0}}\]                    

    D)  \[7\sqrt{7}\,\,{{T}_{0}}\]

    Correct Answer: D

    Solution :

     \[{{T}^{2}}\propto {{r}^{3}}\] law; \[T_{0}^{3}\propto {{R}^{3}}\] & \[T_{s}^{2}\propto {{(<7R)}^{3}};\] \[{{\left( \frac{{{T}_{s}}}{{{T}_{0}}} \right)}^{2}}={{7}^{3}};\]        \[{{T}_{s}}=7\sqrt{7}{{T}_{0}}\]

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