JEE Main & Advanced Sample Paper JEE Main Sample Paper-19

  • question_answer The adjacent figure shows the position graph of one dimensional motion of a particle of mass 4 kg. The impulse at \[t=0\,s\] and \[t=4\]is given respectively as:

    A)  \[0,0\]

    B)  \[0,-3\,kg\,m{{s}^{-1}}\]

    C)  \[+3\,kg\,m{{s}^{-1}},0\]

    D)  \[+3\,kg\,m{{s}^{-1}},-3kg.m{{s}^{-1}}\]

    Correct Answer: D

    Solution :

     \[t<0,\,{{v}_{i}}=0\]and \[t>0,\,{{v}_{f}}=\frac{3}{4}m/s\] \[\therefore \] Impulse \[=m({{v}_{f}}-{{v}_{i}})=4\left( \frac{3}{4}-0 \right)\]                 \[=3\,kg\,m{{s}^{-1}}\] Little before 4 second \[v=\frac{3}{4}m/s,\] little after 4 second, velocity becomes zero Therefore, Impulse \[=m({{v}_{f}}-{{v}_{i}})=4\left( 0-\frac{3}{4} \right)=-3kg\,m{{s}^{-1}}\]

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