A) \[\frac{1}{\pi (2\pi fL-R)}\]
B) \[\frac{1}{2\pi (2\pi fL-R)}\]
C) \[\frac{1}{\pi f(2\pi fL+R)}\]
D) \[\frac{1}{2\pi f(2\pi fL+R)}\]
Correct Answer: D
Solution :
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