• # question_answer 64) The probability of getting the sum more than$7$ when a pair of dice is tossed is A) $\frac{1}{9}$                                   B) $\frac{1}{4}$C) $\frac{7}{12}$                                D) $\frac{5}{12}$

Sum of $7$ can be obtained when$(2,\,\,6),\,\,(3,\,\,5)(3,\,\,6),\,\,(4,\,\,4),$$(4,\,\,5),\,\,(4,\,\,6)(5,\,\,3)$$(5,\,\,4)(5,\,\,5)(5,\,\,6)(6,\,\,2)(6,\,\,3)$$(6,\,\,4)(6,\,\,5)(6,\,\,6)$ $\therefore$Probability of sum$>7=\frac{15}{36}=\frac{5}{12}$