DIRECTIONS (Qs 52): Read the following passage and answer the questions that follows |
A block of mass \[15\text{ }kg\] is placed over a frictionless horizontal surface. Another block of mass \[10\text{ }kg\] is placed over it, that is connected with a light string passing over two pulleys fastened to the \[15\text{ }kg\] block. A force \[F=80N\]is applied horizontally to the free end of the string. Friction coefficient between two blocks is\[0.6\]. The portion of the string between \[10kg\] block and the upper pulley is horizontal. Pulley string and connecting rods are massless. (Take \[g=10\text{ }m/{{s}^{2}}\]) |
A) \[8\text{ }m/{{s}^{2}}\]
B) \[4\text{ }m/{{s}^{2}}\]
C) \[\text{3}\text{.2 }m/{{s}^{2}}\]
D) \[\text{4}\text{.8 }m/{{s}^{2}}\]
Correct Answer: B
Solution :
If \[F=120N,\] then there will be slipping, so using FBDs of both (friction will be 60 N) For \[10\,kg\]block, \[120-60=10a\Rightarrow a=6\,m/{{s}^{2}},\] For \[15\text{ }kg\] block, \[60=50a\Rightarrow a=4m/{{s}^{2}}\].You need to login to perform this action.
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