A) \[85.36%\]
B) \[14.64%\]
C) \[58.63%\]
D) \[26.14%\]
Correct Answer: B
Solution :
Let the amount of the \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] in the mixture be x g, then amount of \[KMn{{O}_{4}}\]will be \[(0.5-x)g\] \[\therefore \] \[\left( \frac{x}{49}+\frac{0.5-x}{31.6} \right)=\frac{100\times 0.15}{1000}\] where 49 is Eq. wt. of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] and \[3.16\] is Eq. wt. of \[KMn{{O}_{4}}\]. On solving, we get \[x=0.073\text{ }g\] % age of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}=\frac{0.0732\times 100}{0.5}=14.64%\]You need to login to perform this action.
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