A) \[6.275\,mm\]
B) \[6.375\,mm\]
C) \[5.75\,mm\]
D) \[5.50\,mm\]
Correct Answer: A
Solution :
Pitch = 1 mm Number of divisions on circular scale = 200 \[L.C=\frac{Pitch}{Number\,ofdivisions\,on\,circular\,scale}\] \[=\frac{1\,mm}{200}=0.005\,mm=0.0005\,cm\] Diameter of the wire = (Main scale reading + Circular scale reading \[\times \] L.C.) - zero error \[=6\,mm+45\times 0.05-(-0.05)\] \[=6\,mm+0.225mm+0.05mm=6.275\,mm\]You need to login to perform this action.
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