A) \[1:5\]
B) \[1:4\]
C) \[1:2\]
D) \[1:1\]
Correct Answer: C
Solution :
Einstein equation KE = E - Work function; \[\frac{1}{2}m{{v}^{2}}=E-W\] Using this concept, \[\frac{\frac{1}{2}mV_{1}^{2}\max }{\frac{1}{2}V_{2}^{2}\max }=\frac{1-.5}{2.5-.5}=\frac{1}{4}\] or \[\frac{{{V}_{1}}\max }{{{V}_{2}}\max }=\frac{1}{2}\]You need to login to perform this action.
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