A) 1 atm
B) 4/5 atm
C) 4/3 atm
D) 3/2 atm
Correct Answer: C
Solution :
Initial pressure, \[{{p}_{1}}={{p}_{2}}={{p}_{0}}=\frac{nR{{T}_{0}}}{{{V}_{0}}}\] when \[{{p}_{0}}=1\]atm. \[{{T}_{0}}=300K.\]You need to login to perform this action.
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