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JEE Main & Advanced Sample Paper JEE Main Sample Paper-1

  • question_answer
    A particle is moving along X-axis, under the action of a variable force which is providing position varying acceleration described by the equation, d = 3x - 4. At t = 0, \[x=\frac{4}{3}m\]and v = 0, Find the velocity and position of particle at t = 5 s.

    A)  0 m/s, 0 m         

    B)  \[0,-\frac{8}{3}m\]

    C)  0 m/s, 4/3m      

    D)  None of these

    Correct Answer: C

    Solution :

    In A is particular question, acceleration at is\[t\approx 0\] \[=3\times \frac{4}{3}-4=0\]and velocity is also zero at t = 0, so particle will remain at rest. Hence, v = 0 and \[x=\frac{4}{3}m\] [initial position].


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