question_answer

In benzilic acid rearrangement

A)  benzaldehyde is converted into benzoin

B)  benzoin is converted into benzilic acid

C)  benzilic acid is converted into benzil

D)  benzil is converted into benzilic acid

Correct Answer: D

Solution :

\[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix}  {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}} \\  \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}}\,-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{ } \\  \text{O} \end{smallmatrix}}{\mathop{\text{C}}}\,-\overset{\Theta }{\mathop{\text{O}}}\,\xrightarrow[{}]{{{\text{H}}^{+}}}\] \[{{\text{(}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}})}_{2}}\underset{\text{benzilic}\,\text{acid}}{\mathop{-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\mathop{\text{C}}}\,-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{O} \end{smallmatrix}}{\mathop{\text{C}}}\,-\text{OH}}}\,\]