A) benzaldehyde is converted into benzoin
B) benzoin is converted into benzilic acid
C) benzilic acid is converted into benzil
D) benzil is converted into benzilic acid
Correct Answer: D
Solution :
\[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\overset{\begin{smallmatrix} {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}} \\ \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{C}}}}\,-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ } \\ \text{O} \end{smallmatrix}}{\mathop{\text{C}}}\,-\overset{\Theta }{\mathop{\text{O}}}\,\xrightarrow[{}]{{{\text{H}}^{+}}}\] \[{{\text{(}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}})}_{2}}\underset{\text{benzilic}\,\text{acid}}{\mathop{-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{OH} \end{smallmatrix}}{\mathop{\text{C}}}\,-\underset{\begin{smallmatrix} \text{ }\!\!|\!\!\text{ } \\ \text{O} \end{smallmatrix}}{\mathop{\text{C}}}\,-\text{OH}}}\,\]You need to login to perform this action.
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