A) ethyl orthoformate
B) acetyl chloride
C) n-butyl formate
D) formic acid
Correct Answer: A
Solution :
\[C{{H}_{3}}.C{{H}_{2}}.C{{H}_{2}}MgBr\to \underset{one\,extra\,carbon}{\mathop{C{{H}_{3}}.C{{H}_{2}}.C{{H}_{2}}.CHO}}\,\] Hence, it is ethyl orthoformate Treatment of HCOOH converts\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}MgBr\]into n-propane simply.You need to login to perform this action.
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