A) \[\frac{340}{41}\]sq unit
B) \[\frac{360}{41}\]sq unit
C) \[\frac{320}{41}\]sq unit
D) None of these
Correct Answer: C
Solution :
Equation of given circle is \[{{x}^{2}}+{{y}^{2}}+6x+8y=0\] ?(i) At point (1,1), \[{{S}_{1}}={{1}^{2}}+{{1}^{2}}+6+8\] \[=1+1+6+8=16\] Now, radius r \[r=\sqrt{{{3}^{2}}+{{4}^{2}}}=5\] Area of required triangle \[=\frac{rS_{1}^{3/2}}{{{r}^{2}}+{{S}_{1}}}\] \[=\frac{5\times {{16}^{3/2}}}{{{5}^{2}}+16}\] \[=\frac{320}{41}\]sq unitYou need to login to perform this action.
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