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JEE Main & Advanced Sample Paper JEE Main Sample Paper-1

  • question_answer
    The only cations present in a slightly acidic solution are \[F{{e}^{3+}},Z{{n}^{2+}}\]and \[C{{u}^{2+}}\]. The reagent that when added in excess to this solution would identify and separate \[F{{e}^{3+}}\] in one, step is

    A) \[2M\,HCl\]                       

    B) \[6M\,N{{H}_{3}}\]

    C) \[6M\,NaOH\]                  

    D) \[{{H}_{2}}S\,gas\]

    Correct Answer: B

    Solution :

    \[F{{e}^{3+}}+Z{{n}^{2+}}+C{{u}^{2+}}\xrightarrow[6M\,N{{H}_{3}}]{{}}\underset{brown\,ppt.}{\mathop{Fe{{(OH)}_{3}}}}\,\] \[+\underset{so\operatorname{lub}le}{\mathop{{{[Zn{{(N{{H}_{3}})}_{4}}]}^{2+}}}}\,+\underset{so\operatorname{lub}le}{\mathop{{{[Cu{{(N{{H}_{3}})}_{4}}]}^{+}}}}\,\]


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