A) \[\alpha \]
B) \[2\alpha \]
C) \[\frac{\alpha }{2}\]
D) None of these
Correct Answer: A
Solution :
Let \[p({{x}_{1}},{{y}_{1}})\] be any point on the circle \[{{x}^{2}}+{{y}^{2}}+2gx+2fy=c=0\] Then, the length of the tangents drawn from \[p({{x}_{1}},{{y}_{1}})\] to the circle \[{{x}^{2}}+{{y}^{2}}+2gx+2fy+c{{\sin }^{2}}\alpha \] \[+({{g}^{2}}+{{f}^{2}}){{\cos }^{2}}\alpha =0\]is \[PQ=PR\]You need to login to perform this action.
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